Calculating the loads and pressures related to a Bentley piston failure.
| Identifier | ExFiles\Box 86\2\ scan0116 | |
| Date | 27th October 1933 | |
| X236 To E. {Mr Elliott - Chief Engineer} from Hs {Lord Ernest Hives - Chair} /Rm. {William Robotham - Chief Engineer} Hs {Lord Ernest Hives - Chair} /Rm. {William Robotham - Chief Engineer} 2/KT.27.10.33. PISTON FAILURE BENTLEY. Referring to our conversation, taking (a) Piston weight 1 lb., (b) Piston weight above gudgeon pin .8 lbs., (c) Maximum inertia at 4500 R.P.M. (d) Maximum explosion at 2000 R.P.M. (e) I.M.E.P. 1.2 M.M.E.P. at 2000 R.P.M., (f) Maximum explosion pr. {Percy H. Rose} 6.6-1 c/r 550, we get - (1) Maximum inertia load tending to break the gudgeon pin boss in tension = Piston top weight x accn. at 4500 = 1300 lbs. approx. (2) Maximum explosion pressure tending to break gudgeon pin boss in compression = I.M.E.P. at 2000 R.P.M. x Piston area - total weight of piston x accn. at 2000 = 4400 lbs. - 400 = 4000 lbs. approx. Maximum compression load about three times maximum inertia load. Hs {Lord Ernest Hives - Chair} /Rm. {William Robotham - Chief Engineer} | ||
From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).