Scheme with mathematical formulas for determining the center of gravity of a vehicle by tilting it.
| Identifier | ExFiles\Box 41\3\ Scan318 | |
| Date | 1st January 1930 | |
| V3730 SCHEME FOR COMPARING THE WEIGHTS AND CENTRES OF GRAVITIES OF VARIOUS BODIES (Gd 1040/30) The weight resting on the off-side and the near-side pairs of the car wheels is estimated. The car is then jacked up on one side about 1 ft. with the other wheels resting on the weighing machine. The exact height the car is raised is noticed, and the exact weight. The jacks can then be raised or lowered a little and a second reading taken. If the weight is evenly distributed when the car is in a horizontal position, Case 1. applies; if not, Case 11. Case I Let T = track of the car (a line joining the pt. of contact of tyres). Let H = height the wheels one side are raised. Let W1, W2 = the wts on the respective sides (W1, W2) Let W = Total weight of car = w1+w2 Let P be the pt. where the line of action of the C of G cuts the track. Let d be the pt P's displacement from the centre of the track T. Then W1/W2 = (T/2 + d) / (T/2 - d) or W1 T/2 - W1 d = W2 T/2 + W2 d or T(W1-W2)/2 = d(W2+W1) or T/d = (W2+W1)2 / (W1-W2) or d = T * (W1-W2)/(2(W2+W1)) = T(W1-W2)/2W Now Sin θ = h {Arthur M. Hanbury - Head Complaints} /T ∴ Tan θ = Tan(Sin⁻¹ h {Arthur M. Hanbury - Head Complaints} /T) ∴ x tan θ = d = T(W1-W2)/2W ∴ x = T(W1-W2)/(2Wtanθ) = T(W1-W2)/(2WTan(Sin⁻¹ h {Arthur M. Hanbury - Head Complaints} /T)) | ||
From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).