From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Calculations for bearing loads and spring torque on a mechanical component under different force conditions.
| Identifier | ExFiles\Box 13\4\ 04-page151 | |
| Date | 2nd May 1933 guessed | |
| -3- [Diagram of a beam with points A and B. Dimensions from left to right: 2 3/4", 5/8", 1.2". A force of 3 1/4 lbs acts upwards at a point 5/8" to the right of B. A force of 3.4 lbs acts downwards at the far right end. There is also a dotted arrow pointing downwards at the same point as the 3 1/4 lbs force.] Load on B. = (3.4 x 4.575 - 3 1/4 x 3 7/8) / 2.75 = 1.05 lbs. this acts vertically downwards on control side bush, i.e. right hand side. Load on A.{Mr Adams} = 3 1/4 - 3.4 x 1.05 = 1.4 lbs. ∴ Load on left hand bearing = 17.6 + 1.4 = 19 lbs. " " right " " = 17.6 - 1.05 = 16.55 lbs. Modified Lec.3412. i.e. Spring on other side of spindle. Throttle closed, 18" Hg. depression. Frictional torque, 1.19 lbs.ins. Spring torque, 3.12 lbs.ins. Excess of spring torque over frictional torque = 162% of frictional torque. Bearing Loads. As before, load on each bearing due to depression = 17.6 lbs. Referring to previous figure, the only difference is that the direction of the 3 1/4 lbs. spring force will be reversed as shown by dotted arrow, and the force on control lever is reduced to 3 lbs. Load on B. = (3 x 4.575 + 3 1/4 x 3 7/8) / 2.75 = 9.6 lbs. Load on A.{Mr Adams} = 9.6 - 3 1/4 - 3 = 2.85 lbs. Load on L.H.B. = 17.6 + 2.85 = 20.45 lbs. " " R.H.B. = 17.6 - 9.6 = 8 lbs. ------ Hs{Lord Ernest Hives - Chair}/C.S.Steadman. | ||