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From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Page of calculations to determine the best depth of a slot in an armature.

Identifier  ExFiles\Box 68\4\  scan0230
Date  1st January 1925 guessed
  
X. 1640

BEST DEPTH OF SLOT IN ARMATURE

Armature dia. = D
Depth of slot = h
No. of slots = n
Total area = A
Area per slot = a
Width of slot = w
Pitch at bottom of slot = p

a = A/n, w = A/nh

p = (π(D - 2h))/n

Width of tooth at root
= x = p - w = 1/n { π(D - 2h) - A/h }

Total C.S. area of teeth at roots
q = nlx = l { π(D - 2h) - A/h }

dq/dh{D. Henderson - Showroom} = l { -2π + A/h² } = 0 for maximum q

h² = A/2π or h = A/2π for best result.
  
  


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