From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Page 2 of a report detailing heat transfer calculations using a calorimeter.
Identifier | ExFiles\Box 58\2\ Scan129 | |
Date | 14th June 1934 guessed | |
F.I.M.A.C. MILANO -2- in same however). 600" were required to bring the temperature of the calorimeter from 30 to 35°, and therefore the heat given by the heater to the calorimeter at 1" is of calories 0,389 -------- = 0,00065 600 2.- Determination of the time required to heat the calorimeter from 30 to 35° with the electrode dipped in the mercury bath and with the copper pin inside the electrode, detached. The time was found to be 240". Hence the heat which passed through the electrode, plus that given by the heater to the calorimeter is: 0,389 -------- = 0,00162 240 and by taking away from same that which was given by the heater to the calorimeter and previously found, it will be: Qs = 0,00162 - 0,00065 = 0,00097 This quantity of heat for 1" is due to the jump of temperature existing between the mercury in which the electrode's head is dipped, and the temperature of the calorimeter. This jump is 117,5° on an average. Hence the coefficient of transmission As of the nucleus per hour in the aforesaid conditions and for one degree of a jump, will be: As = 0,00097 -------- x 3600 = 0,0297 117,5 3.- Determination of the time required to heat the calorimeter from 30 to 35° in the previous conditions, but with a contact copper pin. -------- This time was found to be 140". The heat passed through the electrode plus that given by the heater to the calorimeter is: | ||