Calculations for the resistance and cross-sectional area of an armature turn.
| Identifier | ExFiles\Box 35\4\ scan 145 | |
| Date | 30th April 1923 guessed | |
| -3- Contd. Assumed { RA = .0100 ohm Approx. { RP = .0115 " division. { RB {R. Bowen} = .0025 " Resistance of one armature turn = (.0100 x 4) / 37 = .00108 ohm. Length of armature turn = 11" approx. Resistance per 1000' = (12000 / 11) x .00108 = 1.177 ohms. Butohms per 1000' at 20°C - .00815 ÷ cross sectional area (a) Whence a = .00815 / 1.177 = .00692 sq. ins. Contd. | ||
From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).