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From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Page of calculations and a diagram relating to vehicle weight distribution and center of gravity.

Identifier  ExFiles\Box 5\2\  02-page129
Date  1st December 1927 guessed
  
contd :- -2-

A.{Mr Adams} is front axle of wt. ma
B. is rear " " mb
G.{Mr Griffiths - Chief Accountant / Mr Gnapp} is c.g. of whole car including axles.
E.{Mr Elliott - Chief Engineer} is c.g. of axles (together).
F.{Mr Friese} is c.g. of sprung part of car.

F.{Mr Friese} will lie on the line joining E.{Mr Elliott - Chief Engineer} and G.{Mr Griffiths - Chief Accountant / Mr Gnapp}

c/d = mb/ma = 1.59 ∴ d = 4.17'
c = 6.63'

E G = √DE² + DG² = 1.66'

Then, sprung wt. X F G = unsprung wt. X E G.{Mr Griffiths - Chief Accountant / Mr Gnapp}
∴ F G = .408'

Also k²F = k² about F.{Mr Friese}
k²G = " " G.{Mr Griffiths - Chief Accountant / Mr Gnapp}

And since the k² about its c.g. is the minimum
body can have in any particular plane,

∴ k²G = k²F + FG²
  
  


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