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From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Page of mathematical calculations for the efficiency of a worm and nut mechanism.

Identifier  ExFiles\Box 67\4\  scan0332
Date  13th July 1927 guessed
  
contd :- -2-

∴ Fw / Fn = (sin θ cos γ + sin γ cos θ) / cos γ
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(cos θ cos γ - sin θ sin γ) / cos γ

= sin(θ+γ) / cos(θ+γ) = tan(θ+γ)

To find the efficiency when acting as in diagram :

Let δ = 'lead' of nut (or worm).
Then work done by nut = Fn . δ and
work done by worm = 2πr Fw

but δ / 2πr = tan θ

[Diagram of a right-angled triangle with sides labelled 'δ' (opposite), '2πr' (adjacent), and angle 'θ']

∴ η = (Fn δ) / (2πr Fw) = (2πr tan θ Fn) / (2πr Fw)

= tan θ (Fn / Fw) = tan θ / tan(θ+γ)

Efficiency when 'parking' is expressed :

by η = tan θ / tan(θ+γ)

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contd :-
  
  


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