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From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Calculation of the effect of wheel rotation on braking, comparing translational and rotational kinetic energy.

Identifier  ExFiles\Box 5\3\  03-page072
Date  28th December 1922
  
X4257
28.12.22.
EFFECT OF WHEEL ROTATION ON BREAKING. GII
(No account taken of brake drums.)

Kinetic Energy of translation of car at 60 m.p.h.
.= 1/2 m v^2 / g ft. lbs.
m = 4000 lbs, v = 88f.p.s. g = 32.fts^2
= (2000 X 88 X 88) / 32 = 484,000 ft.lbs.
Kinetic energy of car = 484,000 ft.lbs.

Kinetic Energy of Rotation of one wheel at 60 m.p.h.
.= 1/2 I ω^2 / g ft.lbs.
where I = movement of inertia
ω = angular velocity.(rads per sec)

Now for a wheel I = M a^2 / 2
Where M = mass of wheel, a = semi axis perp. to motion.
and M = 71 lbs., a = approx. 17 ins.
∴ I = (71 X 17 X 17 X 1) / (12 * 12 * 2) = 71 approx.
Also ω = v / r = 88 / 1.42 = 60 approx.

.= 1/2 I ω^2 / g = (71 X 60 X 60) / (32 X 2) = 4,000 ft.lbs.
K.E. of rotation of all 4 wheels = 16,000 ft.lbs. approx.

∴ % of K.E. attributable to wheel rotation = (16 X 100) / 500 = 16/5 = 3.2%

Rm{William Robotham - Chief Engineer}
  
  


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