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From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Calculations for horsepower required for an air jet system.

Identifier  ExFiles\Box 27a\3\  Scan181
Date  31th March 1931 guessed
  
x4516.

Area of jet - 25 sq ft
Velocity of air 85 M.P.H.
Quantity of air/min in lbs
= 25 x 85 x 88 x .08 = 18,600 lbs

K.E. of air = MV^2 / 2g
= (124^2 x 18600) / 64 ft.lbs.

This is generated every min.

∴ Work done/min = (124^2 x 18600) / (64 x 33,000) = 133 H.P.

Assuming 50% efficiency this requires a motor of 266 H.P.

- Reduce free air area to 9 sq FT
- Reduce vel. to 70 M.P.H
Then H.P. required = 260 x (9/25) x (49/72)
= 62.1 H.P. ✓

[Scratchpad]
9.00 / 80

124
x 124
-----
124
248
496
-----
15366

2 33000
  
  


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