From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Page of a technical analysis involving mathematical equations and variables.
Identifier | ExFiles\Box 59\1\ Scan277 | |
Date | 21th February 1928 guessed | |
-2- as a relation between W and R which must hold for any steady condition. Since at the operating point W = W_o = C^2 R, and γ/β R_a is a constant, unless dW/dR = γ/β > dW_o/dR = C^2 the switch can never operate, i.e. not at any voltage, because W can never catch up with W_o.{Mr Oldham} If the limit assigned to V is V_m, then R has a limit V_m/C and W_o a limit V_m C. But W then = γ/β (R - R_a) = γ/β (V_m/C - R_a) so that in order that the switch may operate within the limit of V_m V_m/c - R_a < β/γ V_m . C i.e. β/γ V_m . C^2 + R_a . C - V_m < 0 Solving the quadratic :- C < [ +sqrt(R_a^2 + 4(β/γ)V_m^2) - R_a ] / [ 2(β/γ)V_m ] Contd. | ||