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From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).
Page of a technical analysis involving mathematical equations and variables.

Identifier  ExFiles\Box 59\1\  Scan277
Date  21th February 1928 guessed
  
-2-

as a relation between W and R which must hold for any steady condition.

Since at the operating point W = W_o = C^2 R,
and γ/β R_a is a constant, unless

dW/dR = γ/β > dW_o/dR = C^2

the switch can never operate, i.e. not at any voltage, because W can never catch up with W_o.{Mr Oldham}

If the limit assigned to V is V_m, then R has a limit V_m/C and W_o a limit V_m C.

But W then = γ/β (R - R_a) = γ/β (V_m/C - R_a)

so that in order that the switch may operate within the limit of V_m

V_m/c - R_a < β/γ V_m . C

i.e. β/γ V_m . C^2 + R_a . C - V_m < 0

Solving the quadratic :-

C < [ +sqrt(R_a^2 + 4(β/γ)V_m^2) - R_a ] / [ 2(β/γ)V_m ]

Contd.
  
  


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