Physics-based analysis for calculating displacement and the center of gravity of a vehicle on an incline.
| Identifier | ExFiles\Box 41\3\ Scan319 | |
| Date | 23th May 1923 guessed | |
| Case 11. Where the line of action of the C of G. {Mr Griffiths - Chief Accountant / Mr Gnapp} is initially displaced. Let M1, M2 be the wts. on the respective sides when the car is standing horizontally ( M1 > M2 ) Then the distance from the pt where its line of action cuts the Track to the centre of the track is again given by :- d = ( T(M1 - M2) ) / ( 2W ) Now when it is canted up the displacement is given by :- D = ( T(w1 - w2) ) / ( 2 W. ) Now the distance z in this case is given by :- D - d = 2 * ( T / (2W) ) * (M1 + M2 - w1 - w2) And the height of the C of G above the base by :- x = ( T (M1 - M2 - w1 + w2) ) / ( 2 W Tan ( Sin^-1 (h {Arthur M. Hanbury - Head Complaints} /T) ) ) | ||
From the Rolls-Royce experimental archive: a quarter of a million communications from Rolls-Royce, 1906 to 1960's. Documents from the Sir Henry Royce Memorial Foundation (SHRMF).